Examples of C part 21 fibonacci series

#include<stdio.h>
main()
{
 int a=0,b=1,num,c,count;
 printf("Enter a number to obtain fibonacci series\n");
 scanf("%d",&num);
 printf("The series is\n");
 printf("%d \n%d\n",a,b);
 count=2;
 while(count<num)
     {
       c=a+b;
       a=b;
       b=c;
       printf("%d\n",c);
       count++;
     }
    }

Output:
Enter a number to obtain fibonacci series
8
The series is
0
1
1
2
3
5
8
13Explanation:

The program starts with intializing
- a - for storing starting number of series
- b - for storing second number of series
- num- for storing the length of series
- c - for temporary(auxiliary) variable
- count-for storing the number of iterations that the loop has undergone
First we print the first two values of series i.e. a and b Now the series is 0,1 before starting fibonacci series
Now the count is stored with value 2(count=2)
The while loop iterates until the count is less than given number num(lenght of series)
- step-1 : Now if num=8(say) ,count=2,a=0,b=1 .
- step-2 : as count is less than count (2 is less than 8 )→ true
  - c=0+1=1 → c=1
  - a=b → a=1
  - b=c → b=1
  - Then c is printed and now series is 0,1,1
  - Then count is incremented → count=3
  - Now values are c=1,a=1,b=1,count=3
- step-3 : as count is less than count(3 is less than 8 ) → true
  - c=a+b=1+1→ c=2
  - a=b → a=1
  - b=c → b=2
  - Then c is printed and now series is 0,1,1,2
  - Then count is incremented → count=4
  - Now values are c=2,a=1,b=2,count=4
- step-4 : as count is less than count(4 is less than 8 ) → true
  - c=a+b=1+2→ c=3
  - a=b → a=2
  - b=c → b=3
  - Then c is printed and now series is 0,1,1,2,3
  - Then count is incremented → count=5
  - Now values are c=3,a=2,b=3,count=5
- step-5 : as count is less than count(5 is less than 8 ) → true
  - c=a+b=2+3→ c=5
  - a=b → a=3
  - b=c → b=5
  - Then c is printed and now series is 0,1,1,2,3,5
  - Then count is incremented → count=6
  - Now values are c=5,a=3,b=5,count=6
- step-6 : as count is less than count(6 is less than 8 ) → true
  - c=a+b=3+5→ c=8
  - a=b → a=5
  - b=c → b=8
  - Then c is printed and now series is 0,1,1,2,3,5,8
  - Then count is incremented → count=7
  - Now values are c=8,a=5,b=8,count=7
- step-7 : as count is less than count(7 is less than 8 ) → true
  - c=a+b=5+8→ c=13
  - a=b → a=8
  - b=c → b=13
  - Then c is printed and now series is 0,1,1,2,3,5,8,13
  - Then count is incremented → count=8
  - Now values are c=13,a=8,b=13,count=8
- step-8: as count is not less than count(8 is less than 8 ) → false
- So the final series is 0,1,1,2,3,5,8,13.

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Examples of C part 21 fibonacci series