The Derivative lab

Program: #include &lt stdio.h &gt int main() { int rows; printf("Number of rows: "); scanf("%d",&#34rows); //first loop for printing for(int i=1;i { //second loop for printing similar number in each //rows for(int j=1;j printf("%d",i); } printf("\n"); return 0; }

Subtract series of x^2 till n^2 Program : #include <stdio.h> #include <math.h> main () { //1^2-2^2+3^2-......+n^2 int i , num , sum = 0 ; printf ( "Enter number \n" ); scanf ( "%d" ,& num ); for ( i = 1 ; i <= num ; i ++) { if ( i % 2 == 0 ) { sum -= pow ( i , 2 ); } if ( i % 2 == 1 ) { sum += pow ( i , 2 ); } } printf ( "Sum of series\n" ); for ( i = 1 ; i <= num ; i ++) { if ( i != num ) { if ( i % 2 == 0 ) { printf ( "%d^2+ " , i ); } else { printf ( "%d^2- " , i ); } } else { printf ( "%d^2 = %d\n" , i , sum ); } } } Output : Enter number 6 Sum of series 1^2- 2^2+ 3^2- 4^2+ 5^2- 6^2 = -22 Explanation : //Coming Soon...

Sum series of x^2 till n^2 Program: #include <stdio.h> #include <math.h> main () { //1^2+2^2+3^2+......n^2 int i , num , sum = 0 ; printf ( "Enter number \n" ); scanf ( "%d" ,& num ); for ( i = 1 ; i <= num ; i ++) { sum += pow ( i , 2 ); } printf ( "Sum of series\n" ); for ( i = 1 ; i <= num ; i ++) { if ( i != num ) { printf ( "%d^2+ " , i ); } else { printf ( "%d^2 = %d\n" , i , sum ); } } } Output : Enter number 25 Sum of series 1^2+ 2^2+ 3^2+ 4^2+ 5^2+ 6^2+ 7^2+ 8^2+ 9^2+ 10^2+ 11^2+ 12^2+ 13^2+ 14^2+ 15^2+ 16^2+ 17^2+ 18^2+ 19^2+ 20^2+ 21^2+ 22^2+ 23^2+ 24^2+ 25^2 = 5525 Explanation : //Coming Soon

Geomectry progression Program: #include <stdio.h> #include <math.h> main () { //an=a*r^(n-1) //lastnum=num1*commonratio^(n-1) this is formula from our variables int i , n , sum = 0 , num1 , num2 , commonratio , series , lastnum ; printf ( "Enter first 2 numbers for finding common Difference\n" ); scanf ( "%d%d" ,& num1 ,& num2 ); printf ( "Enter number of terms in series\n" ); scanf ( "%d" ,& n ); commonratio = num2 / num1 ; printf ( "Common Ratio is %d\n" , commonratio ); lastnum =( num1 *( pow ( commonratio ,( n - 1 )))); printf ( "Last term in series is %d\n" , lastnum ); sum =( num1 *( 1 - pow ( commonratio , n )))/( 1 - commonratio ); series = num1 ; printf ( "Sum of the series \n" ); for ( i = 1 ; i <= n ; i ++) { if ( i < n ) { printf ( "%d+" , series ); series *= commonratio ; } else ...

Program : #include <stdio.h> main () { //an=a+(n-1)d int i , n ; float sum = 0 , num1 , diff , lastnum , seriesFirstNum ; printf ( "Enter first number of the series\n" ); scanf ( "%f" ,& num1 ); printf ( "Enter Common difference\n" ); scanf ( "%f" ,& diff ); printf ( "Enter number of terms in the series\n" ); scanf ( "%d" ,& n ); seriesFirstNum = num1 ; lastnum =( float )( num1 +(( n - 1 )* diff )); for ( i = 1 ; i <= n ; i ++) { sum += seriesFirstNum ; seriesFirstNum += diff ; } seriesFirstNum = num1 ; printf ( "Terms present in the Series are:\n" ); for ( i = 1 ; i <= n ; i ++) { if ( i < n ) { printf ( "%.2f," , seriesFirstNum ); seriesFirstNum += diff ; } else { printf ( "%.2f\nSum of the Series is=%.2f\n" , seriesFirstNum , sum ); seriesFirstNu...

Program : #include <stdio.h> #include <math.h> main () { //1^2-2^2+3^2-......+n^2 int i , num , sum = 0 ; printf ( "Enter number \n" ); scanf ( "%d" ,& num ); for ( i = 1 ; i <= num ; i ++) { if ( i % 2 == 0 ) { sum -= pow ( i , 2 ); } if ( i % 2 == 1 ) { sum += pow ( i , 2 ); } } printf ( "Sum of series\n" ); for ( i = 1 ; i <= num ; i ++) { if ( i != num ) { if ( i % 2 == 0 ) { printf ( "%d^2+ " , i ); } else { printf ( "%d^2- " , i ); } } else { printf ( "%d^2 = %d\n" , i , sum ); } } } Output: Enter number 6 Sum of series 1^2- 2^2+ 3^2- 4^2+ 5^2- 6^2 = -22 Explanation: //Coming Soon...

PROGRAM : #include <stdio.h> #include <math.h> main () { //1^2+2^2+3^2+......n^2 int i , num , sum = 0 ; printf ( "Enter number \n" ); scanf ( "%d" ,& num ); for ( i = 1 ; i <= num ; i ++) { sum += pow ( i , 2 ); } printf ( "Sum of series\n" ); for ( i = 1 ; i <= num ; i ++) { if ( i != num ) { printf ( "%d^2+ " , i ); } else { printf ( "%d^2 = %d\n" , i , sum ); } } } Output: Enter number 25 Sum of series 1^2+ 2^2+ 3^2+ 4^2+ 5^2+ 6^2+ 7^2+ 8^2+ 9^2+ 10^2+ 11^2+ 12^2+ 13^2+ 14^2+ 15^2+ 16^2+ 17^2+ 18^2+ 19^2+ 20^2+ 21^2+ 22^2+ 23^2+ 24^2+ 25^2 = 5525 Explanation: //Coming Soon

Program : #include <stdio.h> #include <math.h> main () { //an=a*r^(n-1) //lastnum=num1*commonratio^(n-1) this is formula from our variables int i , n , sum = 0 , num1 , num2 , commonratio , series , lastnum ; printf ( "Enter first 2 numbers for finding common Difference\n" ); scanf ( "%d%d" ,& num1 ,& num2 ); printf ( "Enter number of terms in series\n" ); scanf ( "%d" ,& n ); commonratio = num2 / num1 ; printf ( "Common Ratio is %d\n" , commonratio ); lastnum =( num1 *( pow ( commonratio ,( n - 1 )))); printf ( "Last term in series is %d\n" , lastnum ); sum =( num1 *( 1 - pow ( commonratio , n )))/( 1 - commonratio ); series = num1 ; printf ( "Sum of the series \n" ); for ( i = 1 ; i <= n ; i ++) { if ( i < n ) { printf ( "%d+" , series ); series *= commonratio ; } else { printf ...

Program : #include <stdio.h> main () { //an=a+(n-1)d //lastnum=num1+(n-1)diff this is formula from our variables //n=((an-a)/d)+1 int i , n , sum = 0 , num1 , num2 , diff , lastnum , series ; printf ( "Enter first 2 numbers for finding common Difference\n" ); scanf ( "%d%d" ,& num1 ,& num2 ); printf ( "Enter last term of series\n" ); scanf ( "%d" ,& lastnum ); diff = num2 - num1 ; series = num1 ; n =(( lastnum - num1 )/ diff )+ 1 ; printf ( "Number of terms in series is %d\n" , n ); for ( i = 1 ; i <= n ; i ++) { sum += series ; series += diff ; } series = num1 ; printf ( "Sum of the series\n" ); for ( i = 1 ; i <= n ; i ++) { if ( i < n ) { printf ( "%d+" , series ); series += diff ; } else { printf ( "%d=%d\n" , series , sum ); series += diff ; } ...

P rogram: #include <stdio.h> int factorial ( int ); main () { int i , n ; float sum = 0 ; printf ( "Enter value of n\n" ); scanf ( "%d" ,& n ); for ( i = 1 ; i <= n ; i ++) { sum +=( float ) i / factorial ( i ); } printf ( "The value of\n" ); for ( i = 1 ; i <= n ; i ++) { if ( i < n ) { printf ( "%d/%d!+ " , i , i ); } else { printf ( "%d/%d!= " , i , i ); } } printf ( "%f\n" , sum ); } int factorial ( int num ) { int i , fact = 1 ; for ( i = 1 ; i <= num ; i ++) { fact = fact * i ; } return ( fact ); } Output: Enter value of n 5 The value of 1/1!+ 2/2!+ 3/3!+ 4/4!+ 5/5!= 2.708333 Explanation: //Coming Soon

Program: #include <stdio.h> main () { int i , n ; float sum = 0 ; printf ( "Enter value of n\n" ); scanf ( "%d" ,& n ); for ( i = 1 ; i <= n ; i ++) { sum +=( float ) 1 / i ; } printf ( "The value of\n" ); for ( i = 1 ; i <= n ; i ++) { if ( i < n ) { printf ( "1/%d+ " , i ); } else { printf ( "1/%d= " , i ); } } printf ( "%f\n" , sum ); } Output : Enter value of n 8 The value of 1/1+ 1/2+ 1/3+ 1/4+ 1/5+ 1/6+ 1/7+ 1/8= 2.717857 Explanation: Formula for this series: sum=1+1/2+1/3+1/4....+1/N This program starts with initializing : n  → To store  input from user i  →Used as  helping variable sum  → To store  output sum printf("Enter value of n\n"); scanf("%d",&n); Taking  input from user for(i=1;i<=n;i++) { sum+=(float)1/i; } For loop iterates from  1 to 'n'(say from example 8). Sum  is initialized to  zero Iteration 1 : i=1;1<=8 (wh...

Program : #include <stdio.h> #include <math.h> main () { int a , b , c ; double A , B , C ; const double PI = 3.1415926 ; printf ( "Enter length of a\n" ); scanf ( "%d" ,& a ); printf ( "Enter length of b\n" ); scanf ( "%d" ,& b ); printf ( "Enter length of c\n" ); scanf ( "%d" ,& c ); A = acos ((- pow ( a , 2 )+ pow ( b , 2 )+ pow ( c , 2 ))/( 2 * b * c )); B = acos (( pow ( a , 2 )- pow ( b , 2 )+ pow ( c , 2 ))/( 2 * c * a )); C = acos (( pow ( a , 2 )+ pow ( b , 2 )- pow ( c , 2 ))/( 2 * a * b )); A *= 180 / PI ; B *= 180 / PI ; C *= 180 / PI ; printf ( "Angle of A=%lf\n" , A ); printf ( "Angle of B=%lf\n" , B ); printf ( "Angle of C=%lf\n" , C ); } Output: Enter length of a 2 Enter length of b 3 Enter length of c 4 Angle of A=28.955025 Angle of B=46.567464 Angle of C=104.477514 Explanation: Reference:--- a² = b² +...

Program : #include <stdio.h> #include <math.h> main () { int x1 , x2 , y1 , y2 ; double distance ; printf ( "Enter x1\n" ); scanf ( "%d" ,& x1 ); printf ( "Enter y1\n" ); scanf ( "%d" ,& y1 ); printf ( "Enter x2\n" ); scanf ( "%d" ,& x2 ); printf ( "Enter y2\n" ); scanf ( "%d" ,& y2 ); distance = sqrt (( pow (( x2 - x1 ), 2 ))+( pow (( y2 - y1 ), 2 ))); printf ( "Distance=%lf\n" , distance ); } Output: Enter x1 -2 Enter y1 -3 Enter x2 -4 Enter y2 4 Distance=7.280110 Explanation: //Coming Soon..

Program : #include <stdio.h> main () { int i , j , totPolynomials , maxSize = 0 ; printf ( "Enter Number of Polynomials to add\n" ); scanf ( "%d" ,& totPolynomials ); int polynomials [ totPolynomials ][ 100 ], eachPolynomialSize [ totPolynomials ]; for ( i = 0 ; i < totPolynomials ; i ++) { printf ( "Enter Size of %d Polynomial\n" , i + 1 ); scanf ( "%d" ,& eachPolynomialSize [ i ]); if ( maxSize < eachPolynomialSize [ i ]) maxSize = eachPolynomialSize [ i ]; for ( j = 0 ; j < eachPolynomialSize [ i ]; j ++) { printf ( "Enter x^%d Co-Efficient of %dth Polynomial\n" , j , i ); scanf ( "%d" ,& polynomials [ i ][ j ]); } } int sum [ maxSize ]; for ( i = 0 ; i < maxSize ; i ++) { sum [ i ]= 0 ; } for ( i = 0 ; i < totPolynomials ; i ++) { for ( j = 0 ; j < eachPolynomialSize [ i ]; j ++) { sum [ j ]+= polynomials [ i...