Examples of C part 60 find angles of triangle for given length of sides

• Program :

#include<stdio.h>
#include<math.h>
main()
{
 int a,b,c;
 double A,B,C;
 const double PI =  3.1415926;
 printf("Enter length of a\n");
 scanf("%d",&a);
 printf("Enter length of b\n");
 scanf("%d",&b);
 printf("Enter length of c\n");
 scanf("%d",&c);
 A=acos((-pow(a,2)+pow(b,2)+pow(c,2))/(2*b*c));
 B=acos((pow(a,2)-pow(b,2)+pow(c,2))/(2*c*a));
 C=acos((pow(a,2)+pow(b,2)-pow(c,2))/(2*a*b));
 A*=180/PI;
 B*=180/PI;
 C*=180/PI;
 printf("Angle of A=%lf\n",A);
 printf("Angle of B=%lf\n",B);
 printf("Angle of C=%lf\n",C);

}

Output:
Enter length of a
2
Enter length of b
3
Enter length of c
4
Angle of A=28.955025
Angle of B=46.567464
Angle of C=104.477514Explanation:
Reference:--- a² = b² + c² - 2bc cosA b² = a² + c² - 2ac cosB c² = b² + a² - 2ba cosC